C# Json 字符串时间 转对象




Z 表示时区



根据笔者的校验,建议使用 UNIX 时间戳 形式传递。

C# 快速将当前时间转换为时间戳的代码为(以秒为单位)

(DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000 / 1000


(DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000

C# 时间转换的常用代码

        /// <summary>
        /// 获取1970-01-01至dateTime的秒数,不带时区
        /// </summary>
        public static long GetTimestamp(DateTime dateTime)
            DateTime dt1970 = new DateTime(1970, 1, 1, 0, 0, 0, 0);
            return (dateTime.Ticks - dt1970.Ticks) / 10000 / 1000;

        /// <summary>
        /// 根据时间戳timestamp(单位 秒)计算日期,不带时区
        /// </summary>
        public static DateTime NewDate(long timestamp)
            DateTime dt1970 = new DateTime(1970, 1, 1, 0, 0, 0, 0);
            long t = dt1970.Ticks + timestamp * 10000 * 1000;
            return new DateTime(t);

        /// <summary>
        /// 将字符串转为时间
        /// </summary>
        /// <param name="dateString"></param>
        /// <returns></returns>
        public static DateTime StringToDateTime(string dateString)
            //格式必须为 2019-03-13 14:49:10.8327809
            DateTime dt = Convert.ToDateTime(dateString, System.Globalization.CultureInfo.CurrentCulture);
            return dt;
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